What happens if hashCode() method always returns the same value?
If the hashCode()
method always returns the same value for all objects, the performance of hash-based collections like HashMap
, HashSet
, and Hashtable
will be significantly degraded. Here’s what happens:
Impact on Hash-Based Collections
Hash-based collections like HashMap
or HashSet
use the hash code of an object to decide which “bucket” to place the object in. Ideally, objects with different values should produce different hash codes, spreading the objects evenly across buckets, which makes lookups, insertions, and deletions efficient.
-
If
hashCode()
always returns the same value (e.g.,0
for every object), all objects will be placed in the same bucket. -
This leads to a scenario where the collection behaves like a linked list instead of a hash table.
-
In such cases, the time complexity for operations like
get()
,put()
,remove()
degrades from O(1) (constant time) to O(n) (linear time), wheren
is the number of objects in the collection.
Violation of the Hash Code Contract
While always returning the same value for hashCode()
doesn’t violate the contract between equals()
and hashCode()
, it defeats the purpose of having a hash code in the first place, which is to optimize object lookup and storage.
Example:
Consider the following class with a hashCode()
that always returns 1
:
class Person {
private String name;
private int age;
public Person(String name, int age) {
this.name = name;
this.age = age;
}
@Override
public boolean equals(Object obj) {
if (this == obj) return true;
if (obj == null || getClass() != obj.getClass()) return false;
Person person = (Person) obj;
return age == person.age && Objects.equals(name, person.name);
}
@Override
public int hashCode() {
return 1; // Same hash code for all objects
}
}
If we store multiple Person
objects in a HashMap
or HashSet
, all of them will be placed in the same bucket, leading to poor performance as the collection grows.
Summary:
-
If
hashCode()
always returns the same value, the collection will still work correctly, but the performance will degrade significantly. -
It is crucial to implement a good
hashCode()
method that spreads objects across buckets to take advantage of the constant-time operations offered by hash-based collections.